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Specific calculation example of equivalent cooling power of hydraulic cooler

网责任编辑: 作者: 人气: - 发表时间:2019-07-14 08:00:00【 Article Source: Original Network Editor: Author: Popularity: - Published: 2019-07-14 08:00:00 [ Tai Zhong small ]
   Example of calculation of equivalent cooling power, suitable for hydraulic cooler for hydraulic system
   The known conditions are as follows:
   HAD-90 hydraulic oil
   Required heat dissipation: 58000BTU / hr
   Flow Rate (L / m) *: 115
   Inlet Temperature (℃) *: 60 ℃
   Outlet Temperature (℃) *: 50 ℃
   Maximum ambient temperature: 40 ° C
   具体型号 Inquiry: Please recommend the specific model of hydraulic cooler
   If the data is accurate, the equivalent cooling power can be obtained according to the following calculation
   Cooling power = 58000x0.3 / 1000 = 17.4kw
   Take the safety factor as 1.1
   Then there are: 17.4x1.1 = 19.14kw
   When the ambient temperature is 40 ℃, the oil temperature is required to be controlled at 50 ℃
   Then
   Equivalent cooling power = 19.14 ÷ (50-40) = 1.914kw / ℃
   When the flow rate is 115L / min
   Select HD6042T-380Ⅴ
   Note: Because the 460V, 60Hz motor is not a standard product that the manufacturer always prepares, it must be customized.
   专利产品,性能优良,安装维护方便。 The patented product of HD series hydraulic cooler , which was developed exclusively by Heyida manufacturers, has excellent performance and convenient installation and maintenance.
HD6042T液压冷却器
液压冷却器 Keywords in this article: Hydraulic cooler