Known conditions: 5000L fuel tank, independent oil pump circulation system of air cooler, 125L / min, requires 1 hour to drop from 95 ℃ to 60 ℃.
Heating power Pv calculation
Pv = ρxV × Cx △ T / H
= 0.88x5000x2.15x (95-60) /60x60=91.972kw
Assuming the maximum ambient temperature is 40 ° C,
The actual temperature difference is:
T1 ~ T2 = 95-40 = 55 ℃
Equivalent cooling power of air cooler
P1 = Pv / (T1-T2)
= 91.972 / 55 = 1.67kw / ℃
Select 10% safety margin
Then P1 = 1.67x1.1 = 1.84kw / ℃
Selection: When the circulating oil pump is 125L / min, according to the heat dissipation curve, the maximum equivalent cooling power of our standard product is 1.4kw / ℃, <1.84kw / ℃,
If you do not order non-standard products, you can choose two standard AH2490T in parallel, each of which is equipped with a 120L / min circulating pump, which is the most ideal.
The equivalent cooling power of AH2490T is 1.06kw / ℃, two units: 2x1.06 = 2.12> 1.84kw / ℃, which meets the requirements.
Conclusion: Two AH2490T air coolers are selected, each equipped with Shanghai Guorui 120L / min circulating pump unit.